Modern Physics for Engineers

Problem Set 7

Problem Set - Due in class, Wednesday, Nov. 10, 1999.

    Problems:
  1. SM&M 11-10
    	Density of electrons = density of Ag atoms 
    	    = 10.5 g/cm^3 /107.87 g/mole * 6.022e23 atoms/mole 
    	    = 5.87e22 e's/cm^3 = 5.87e28 e's/m^3
    
    Part A) Collision time:
    	Tau = m_e/(n e^2 rho) 
    	    = 9.1e-31 kg/(5.87e28 e's/m^3 (1.6e-19 coul)^2 1.6e-8 Ohm m
    	    = 3.9e-14 sec
    
    Part B)  Electron termal velocity/Mean free path
    	V_rms = Sqrt[3 k_B T/m_e]
    	      = Sqrt[3 1.38e-23 J/oK 298oK/9.1e-31 kg]
    	      = 1.16e5 m/sec
    	L = v_rms * tau
    	  = 1.16e5 m/sec * 3.9e-14 sec = 4.54e-9 m
    	  = 4.54 nm
    
    Part C)
    	Lattice spacing = 2.6e-10 m --> 17 lattice spacings
    
  2. SM&M 11-13
    Part B)  First
    	Resistivity = rho =Sqrt[2 m E]/(n e^2 L)
    	L = Sqrt[2 m E]/ (n e^2 rho)
    	  = Sqrt[2 * 9.1e-31 kg * 5.48 eV * 1.6e-19 joules/eV]
    	    --------------------------------------------------
    	     5.87e28 e's/m^3 * (1.6e-19 coul)^2 *1.6e-8 ohm m
    	  = 5.25e-8 m = 52.5 nm
    Part A)
    	V_f = Sqrt[2 E_f/m_e] = Sqrt[2*5.48*1.6e-19/9.1e-31] = 1.4e6 m/sec
    	Tau = L/v_f = 5.25e-8 m /1.4e6 m/sec = 3.8e-14 sec
    	   (Note: same collision time as above!!!)
    Part C)
    	Lattice spacing = 2.6e-10 m --> 202 lattice spacings
    	
    
  3. SM&M 11-18
    Part A)
    Room temperature * k_B = .024 eV 
    Binding energy = 13.6 eV * Z^2 (but Z is reduced by polarizability)
    	         = 13.6 eV * (1/12)^2 = .094 eV (Si) = 3.9 * k_b T_room
    	         = 13.6 eV * (1/16)^2 = .053 eV (Ge) = 2.2 * k_b T_room
    Part B)
    Bohr radius = .53e-10 m
    	R_Si = .53e-10 * 12 = 6.4e-10 = 2.7 Lattice spacings 
    	R_Ge = .53e-10 * 16 = 8.5e-10 = 3.5 Lattice spacings
    
  4. SM&M 12-15
    Part A)
    	B = mu_0 n I (where n = turns/m)
    	I = B/(n mu_0) = 10 T/(2000/m 4 Pi 1e-7) 
    	  = 3979 amps
    Part B)
    	DF/dl = I B = 3979 amps * 10 T = 4.0e4 N/m
    
  5. SM&M 12-29
    Part A)
    	Delta E = 2 mu B = 2 5.79e-5 eV/T 38 T
    	        = 4.4e-3 eV
    Part B)
    	E_gap = 3.53 k T_c = 3.53*8.6e-5 eV/oK 23oK = 7.0e-3 eV
    
    Part C)
    The numbers are comparable. Thus approximately the same Mechanicism must be resposible for the end of superconductivity At high magnetic fields and at high temperatures.