Problems:
- SM&M 11-10
Density of electrons = density of Ag atoms
= 10.5 g/cm^3 /107.87 g/mole * 6.022e23 atoms/mole
= 5.87e22 e's/cm^3 = 5.87e28 e's/m^3
Part A) Collision time:
Tau = m_e/(n e^2 rho)
= 9.1e-31 kg/(5.87e28 e's/m^3 (1.6e-19 coul)^2 1.6e-8 Ohm m
= 3.9e-14 sec
Part B) Electron termal velocity/Mean free path
V_rms = Sqrt[3 k_B T/m_e]
= Sqrt[3 1.38e-23 J/oK 298oK/9.1e-31 kg]
= 1.16e5 m/sec
L = v_rms * tau
= 1.16e5 m/sec * 3.9e-14 sec = 4.54e-9 m
= 4.54 nm
Part C)
Lattice spacing = 2.6e-10 m --> 17 lattice spacings
- SM&M 11-13
Part B) First
Resistivity = rho =Sqrt[2 m E]/(n e^2 L)
L = Sqrt[2 m E]/ (n e^2 rho)
= Sqrt[2 * 9.1e-31 kg * 5.48 eV * 1.6e-19 joules/eV]
--------------------------------------------------
5.87e28 e's/m^3 * (1.6e-19 coul)^2 *1.6e-8 ohm m
= 5.25e-8 m = 52.5 nm
Part A)
V_f = Sqrt[2 E_f/m_e] = Sqrt[2*5.48*1.6e-19/9.1e-31] = 1.4e6 m/sec
Tau = L/v_f = 5.25e-8 m /1.4e6 m/sec = 3.8e-14 sec
(Note: same collision time as above!!!)
Part C)
Lattice spacing = 2.6e-10 m --> 202 lattice spacings
- SM&M 11-18
Part A)
Room temperature * k_B = .024 eV
Binding energy = 13.6 eV * Z^2 (but Z is reduced by polarizability)
= 13.6 eV * (1/12)^2 = .094 eV (Si) = 3.9 * k_b T_room
= 13.6 eV * (1/16)^2 = .053 eV (Ge) = 2.2 * k_b T_room
Part B)
Bohr radius = .53e-10 m
R_Si = .53e-10 * 12 = 6.4e-10 = 2.7 Lattice spacings
R_Ge = .53e-10 * 16 = 8.5e-10 = 3.5 Lattice spacings
- SM&M 12-15
Part A)
B = mu_0 n I (where n = turns/m)
I = B/(n mu_0) = 10 T/(2000/m 4 Pi 1e-7)
= 3979 amps
Part B)
DF/dl = I B = 3979 amps * 10 T = 4.0e4 N/m
- SM&M 12-29
Part A)
Delta E = 2 mu B = 2 5.79e-5 eV/T 38 T
= 4.4e-3 eV
Part B)
E_gap = 3.53 k T_c = 3.53*8.6e-5 eV/oK 23oK = 7.0e-3 eV
Part C)
The numbers are comparable. Thus approximately the same
Mechanicism must be resposible for the end of superconductivity
At high magnetic fields and at high temperatures.