Given
A load ZL=RL+jXL or a load having a Reflection Coefficent GL=rejq to be matched to a transmission line of charactersitic impedance of Zc. The matching will be done using a single stub shunt element.
The matching network will look like this:
Since a shunt elemnt will be added to the network, Admittance rather than Impedance will be usefull.
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- Locate
on the Smith Chart as shown in the figure.
- The normalized ZL or
- The Reflection Coeficient rejq
- Locate the corresponding Load Admittance YL. [180o with the same rL].
- From now on the chart becomes an ADMITTANCE CHART
- Draw a circle with radius rL.
- Move on this constant circle TOWARD THE GENERATOR until G=1 circle is intersected.
- At this point, you have reached 1+jB1
- Actually there are two points that may be intersected on the G=1 circle. These are either 1+jB1 or 1-jB2.
- The length of the transmission line to reach 1+jB1 is d1. This can be read from the periphery of the Smith Chart.
- If we now add a shunt element (either open-circuited or short-circuited) equal to -jB1 or +jB2, we will reach the center of the Smith Chart.
Figure Below shows how to find the length d2 of an open-circiuted line so that it will give an admittance -jB1 to be added as a shunt element to the Transmiion line
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Experiment (1) (2) (3) (4) (5) (6)
Additional Notes
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